The chemical equation for the combustion reaction occurring when acetylene (C2H2) is burned in welding torches

The chemical equation for the combustion reaction occurring when acetylene (C2H2) is burned in welding torches is as follows:

2C2H2(g) + 5O2(g) ® 4CO2(g) + 2H2O(l)

How many moles of water will be produced when 65.2 g of acetylene (C2H2) are completely burned?

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2 Responses to “ The chemical equation for the combustion reaction occurring when acetylene (C2H2) is burned in welding torches ”

  1. 65.0g C2H2 = 2.5mol (65gC2H2 x 1mol/26g)

    Assuming you have excess O2,
    2.5mol C2H2 x (2mol H2O / 2mol C2H2) = 2.5mol C2H2.

    Technically C2H2 and H2O in the equation have same stoichiometric moles (2 C2H2 = 2 H2O) so you get same moles of H2O as your moles of C2H2.

  2. Number of moles of water produced
    = Mass of acetylene / Molecular mass of acetylene x Molecular mass of water
    = (65.2 / 26 x 18) mol

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